x=2.61 radians
Explanation
[tex]2\cos (x)+\sqrt[]{3}=0[/tex]
Step 1
Let's isolate x
a)
[tex]\begin{gathered} 2\cos (x)+\sqrt[]{3}=0 \\ \text{subtract }\sqrt[]{3}\text{ in both sides} \\ 2\cos (x)+\sqrt[]{3}-\sqrt[]{3}=0-\sqrt[]{3} \\ 2\cos (x)=-\sqrt[]{3} \end{gathered}[/tex]
Step 2
b) now, divide both sides by 2
[tex]\begin{gathered} 2\cos (x)=-\sqrt[]{3} \\ \text{divide both sides by 2} \\ \frac{2\cos(x)}{2}=\frac{-\sqrt[]{3}}{2} \\ \cos (x)=\frac{-\sqrt[]{3}}{2} \\ \end{gathered}[/tex]Step 3
c) finally,Inverse cosine in both sides ( remember we are looking for an angle)
[tex]\begin{gathered} \cos (x)=\frac{-\sqrt[]{3}}{2} \\ \text{ Inverse cosine in both sides} \\ \cos ^{-1}(\cos (x))=\cos ^{-1}(\frac{-\sqrt[]{3}}{2}) \\ x=\cos ^{-1}(\frac{-\sqrt[]{3}}{2}) \\ x=\cos ^{-1}(-0.86) \\ x=2.61\text{ radians} \end{gathered}[/tex]therefore, the answer is
x=2.61 radians
I hope this helps you