Question

Plot five points on the graph of the function:one point with x=0, two points with negative x-values and two points with positive x-values.

Answer 1

Given

$y=-\frac{5}{8}x^3$

First calculate the ordered pairs for each point, to do so, select the values of x, replace them in the equation of the function, and then calculate the corresponding y-values

I'll calculate the values for x=-2, x=-1, x=0, x=1, x=2

For x=-2

$\begin{gathered} y=-\frac{5}{8}(-2)^3 \\ y=(-\frac{5}{8})\cdot(-8) \\ y=5 \end{gathered}$

The first ordered pair is (-2,5)

For x=-1

$\begin{gathered} y=-\frac{5}{8}(-1)^3 \\ y=(-\frac{5}{8})(-1) \\ y=\frac{5}{8} \end{gathered}$

The second ordered pair is (-1,5/8)

For x=0

$\begin{gathered} y=-\frac{5}{8}\cdot0^3 \\ y=0 \end{gathered}$

The third ordered pair is (0,0)

For x=1

$\begin{gathered} y=-\frac{5}{8}(1^3) \\ y=-\frac{5}{8} \end{gathered}$

The fourth ordered pair is (1,-5/8)

For x=2

$\begin{gathered} y=-\frac{5}{8}(2^3) \\ y=-\frac{5}{8}\cdot8 \\ y=-5 \end{gathered}$

The fifth ordered pair is (2,-5)

Once you have determined all ordered pairs you can plot the five points.