we wirte the expression on numbers
[tex]15-\frac{x}{3}=7[/tex]where x is the missing number
to solve
subtract 15 on both sides
[tex]\begin{gathered} 15-15-\frac{x}{3}=7-15 \\ -\frac{x}{3}=-8 \end{gathered}[/tex]we can remove negative sign on both sides
[tex]\begin{gathered} \frac{x}{3}=8 \\ \end{gathered}[/tex]and solve for x multipliying 3 on both sides
[tex]\begin{gathered} 3\times\frac{x}{3}=8\times3 \\ \\ x=24 \end{gathered}[/tex]the value of missing number is 24
Other way
[tex]15-\frac{x}{2}=7[/tex]
solve for x moving terms
[tex]\begin{gathered} -\frac{x}{3}=7-15 \\ \\ -\frac{x}{3}=-8 \\ \\ x=-8\times-3 \\ \\ x=24 \end{gathered}[/tex]