Question

Which value of x satisfies the equation 1/6 (x+ 1/2 )= 19/12 ?

Answer 1

The initial equation is:

$\frac{1}{6}(x+\frac{1}{2})=\frac{19}{12}$

Applying distributive property:

$\frac{1}{6}x+\frac{1}{12}=\frac{19}{12}$

Substracting (1/12) on both sides:

$\begin{gathered} \frac{1}{6}x+\frac{1}{12}-\frac{1}{12}=\frac{19}{12}-\frac{1}{12} \\ \frac{1}{6}x=\frac{18}{12} \end{gathered}$

Multiplying by 6 on both sides:

$\begin{gathered} \frac{1}{6}x\cdot(6)=\frac{18}{12}\cdot(6) \\ x=9 \end{gathered}$

So, the value of x that satisfied the equation is 9.