having that x=3 we get
[tex]3-2y=11\rightarrow-2y=11-3=8\rightarrow y=-\frac{8}{2}=-4[/tex]so the answer is x=3 and y=-4
[tex]x-2y=11\rightarrow x=11+2y[/tex]having that we can replace in the first equation
[tex]\begin{gathered} -7\cdot(11+2y)-2y=-13\rightarrow-77-14y-2y=-13\rightarrow-16y=64 \\ y=-\frac{64}{16}=-4 \end{gathered}[/tex]having that y=-4 we get
[tex]x=11+2\cdot-4=11-8=3[/tex]