We have to calculate the number of beads she uses for every bracelet and for every necklace.
Let B the beads for each bracelet and N the beads for each necklace.
For her family, she assembled 5 bracelets and 2 necklaces, using a total of 221 beads. We can represent this as:
[tex]5B+2N=221[/tex]For her friends, she assembled 9 bracelets and 4 necklaces, using a total of 423 beads. This can be represented as:
[tex]9B+4N=423[/tex]We can solve this by elimination, by substracting two times the first equation from the second equation:
[tex]\begin{gathered} (9B+4N)-2(5B+2N)=423-2(221) \\ 9B+4N-10B-4N=423-442 \\ -1B+0N=-19 \\ B=19 \end{gathered}[/tex]We can now use any of the equations to find the value of N:
[tex]\begin{gathered} 9B+4N=423 \\ 9(19)+4N=423 \\ 171+4N=423 \\ 4N=423-171 \\ 4N=252 \\ N=\frac{252}{4} \\ N=63 \end{gathered}[/tex]Answer: She uses 19 beads for each bracelet and 63 beads for each necklace.