Question

For what values of x is f(x) =-2x - 3 increasing? For whatvalues of x is it decreasing?

Answer 1

Given:

$f(x)=-2x-3$

Differentiate with respect to 'x'

$f^{\prime}(x)=-2$$f^{\prime}(x)<0$

Therefore the function is decreasing.

$\text{The fuction decreasing for the x values (-}\infty,\infty)$