Question

An organ pipe (open at both ends) is 1.23 m long. If the speed of sound is 340 m/s, what is its fundamental frequency?

Answer 1

The fundamental frequency in this case will be given by:

$f_1=\frac{v_s}{2l}$

Where:

$\begin{gathered} _{\text{ }}v_s=Speed_{\text{ }}of_{\text{ }}sound \\ _{\text{ }}l=Length \end{gathered}$

Therefore:

$\begin{gathered} f_1=\frac{340}{2\cdot1.23} \\ f_1=138.211Hz \end{gathered}$

Answer:

138.211 Hz