a) Radius of cylinder, r = 6m
where Height is h and Volume is V
[tex]Volume,V=\pi^{}r^2h[/tex]c) if height is doubled
Replace the h with 2h
[tex]h=2(h)=2h[/tex][tex]V=\pi r^2h^{}[/tex][tex]V=\pi r^2(2h)[/tex]From the equation, the volume will be doubled when the height is doubled.
d) if the height is multiplied by 1/3
Replace h with 1/3(h)
[tex]h=\frac{1}{3}(h)[/tex][tex]V=\pi r^2(\frac{1}{3}h)[/tex]From the equation, the volume of the cylinder will be 1/3 of it's original volume when height is multiplied by 1/3.
b) Where r= 3.14, below lies the graph
[tex]\begin{gathered} V=\pi r^2h \\ \pi=3.14,\text{ r}=6m\text{ substitute for }\pi\text{ and r into the equation above} \\ V=(3.14)(6^2)h=(113.04h)m^3 \end{gathered}[/tex]