Need help writing the equation of the line in fully simplified slope-intercept form

y=4x-5
Explanationthe slope -intercept form of the equation of a line is
[tex]\begin{gathered} y=mx+b \\ where\text{ m is the slope and b is the y-intercept} \end{gathered}[/tex]so
Step 1
find the slope of the line
we can find the slope of a line using the formula
[tex]\begin{gathered} slope=\frac{change\text{ in y}}{change\text{ in x}}=\frac{y_2-y_1}{x_2-x_1} \\ where \\ P1(x_1,y_1) \\ and \\ P2(x_2,y_2)\text{ are 2 points from the line} \end{gathered}[/tex]so
a) let
[tex]\begin{gathered} P1(-1,-1) \\ P2(0,-5) \end{gathered}[/tex]b) now, replace in the formula
[tex]\begin{gathered} slope\frac{}{}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ slope=\frac{-5-(-1)}{0-(-1)}=\frac{-5+1}{1}=-4 \end{gathered}[/tex]Step 2
y-intercept:
now, to find the value of b ( y-intercpet) we need to check in the graph , the point where the lines crosses the y-axis and take the y-coordinate, so
so
b=-5
Step 3
finally, replace
[tex]\begin{gathered} y=mx+b \\ y=-4x-5 \end{gathered}[/tex]so, the equation of the line is
y=-4x-5