A swimming pool is in the form of a semicircular-sided figure

Given:
A swimming pool is in the form of a semicircular-sided figure
Required:
What is the area of the 3 ft wide surrounding the pool?
Explanation:
We will find area as:
[tex]\begin{gathered} A=\text{ Area of semicircle including side walk }-\text{ Area of semicircle without } \\ \text{side walk} \end{gathered}[/tex]Now, radius for smaller semicircle is 5 ft and radius for larger semicircle (5 + 3 = 8)
So,
[tex]\begin{gathered} A=(\frac{3.14\times8^2}{2})-(\frac{3.14\times5^2}{2}) \\ A=100.48-39.25 \\ A=61.23ft^2 \end{gathered}[/tex]If we take walk on both sides, we will multiply it with 2
A = 2*61.23
A = 122.46 ft square
Now, we have one side of bigger rectangle is 10 + 3 + 3 = 16 ft
So,
[tex]\begin{gathered} A\text{ = area of rectangle - area of square} \\ A=(16\times10)-10^2 \\ A=60ft^2 \end{gathered}[/tex]Finally,
[tex]\begin{gathered} A=122.46+60 \\ A=182.46ft^2 \end{gathered}[/tex]Answer:
Hence, above is the answer.