Predict the missing values if the following trials were performed. (No CER required) ∆V = 24 V R = 10 Ω I = _______ A ∆V = 12 V R = 40 Ω I = _______ A ∆V = 6 V I = 4.0 A R = _______ Ω

a)I=2.4 A
b)I=0.3 A
c)1.5 ohms
ExplanationOhm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.it is represented in the equations
[tex]\begin{gathered} V=RI \\ R=\frac{V}{I} \\ I=\frac{V}{R} \end{gathered}[/tex]so
Step 1
a) given
[tex]\begin{gathered} V=24\text{ V} \\ R=10\text{ ohm} \\ I=\text{ unknown} \end{gathered}[/tex]replace in the proper formula, so
[tex]\begin{gathered} I=\frac{V}{R} \\ I=\frac{24\text{ V}}{10\text{ Ohm}}=2.4\text{ A} \end{gathered}[/tex]so
a)I=2.4 A
Step 2
i)let
[tex]\begin{gathered} V=12\text{ V} \\ R=40\text{ ohms} \end{gathered}[/tex]replace
[tex]\begin{gathered} I=\frac{V}{R} \\ I=\frac{12\text{ V}}{40\text{ ohm}}=0.3\text{ A} \end{gathered}[/tex]so
b)I=0.3 A
Step 3
finally, to find the resistenace, let
[tex]\begin{gathered} V=6\text{ V} \\ I=4.0\text{ A} \end{gathered}[/tex]replace in the proper formula
[tex]\begin{gathered} R=\frac{V}{I} \\ R=\frac{6\text{ V}}{4\text{ A}} \\ R=1.5\text{ ohms} \end{gathered}[/tex]so
c)1.5 ohms
I hope this helps you