Question

Assignment X 15 8 8 sin-1 = mZT 15 T 17 U Descibe and correct the error.

Answer 1

$\sin T=\frac{oppos.}{\text{hypo.}}$

The sine function should be the ratio between the opposite side to the angle T and the hypotenuse (opposite side of the right angle)

∵ The opposite side of < T is VU

∵ The hypotenuse is TU

$\therefore\sin T=\frac{VU}{TU}$

∵ VU = 8 and TU = 17

$\therefore\sin T=\frac{8}{17}$

To find the angle T use the inverse of the sine

$m\angle T=\sin ^{-1}(\frac{8}{17})$

But they wrote

$m\angle T=\sin ^{-1}(\frac{8}{15})$

They use the adjacent side of angle T instead of the hypotenuse

Then, 15 must be changed to 17