We have to solve the system of equations for x. The equations are:
[tex]\begin{gathered} 2x+y=72 \\ 3y=48 \end{gathered}[/tex]In this case, we can replace y using the second equation and then solving for x in the first equation.
We find y as:
[tex]\begin{gathered} 3y=48 \\ y=\frac{48}{3} \\ y=16 \end{gathered}[/tex]Then, we replace y in the first equation and we wlll obtain:
[tex]\begin{gathered} 2x+y=72 \\ 2x+16=72 \\ 2x=72-16 \\ 2x=56 \\ x=\frac{56}{2} \\ x=28 \end{gathered}[/tex]Answer: x = 28 [Option A]
