Answer:
[tex]3\sqrt[]{5}[/tex]
Explanation:
We were given the expression:
[tex]6-3i[/tex]
We are to solve for its modulus. This is shown below:
[tex]\begin{gathered} 6-3i \\ \text{The formula for obtaining modulus is given by:} \\ if\colon z=a+bi \\ then\colon|z|=\sqrt[]{a^2+b^2} \\ \Rightarrow\sqrt[]{6^2+(-3)^2} \\ =\sqrt[]{36+9} \\ =\sqrt[]{45} \\ =\sqrt[]{9\times5} \\ =\sqrt[]{9}\times\sqrt[]{5} \\ =3\times\sqrt[]{5} \\ =3\sqrt[]{5} \\ \\ \therefore3\sqrt[]{5} \end{gathered}[/tex]
