Given that
[tex]\Delta BIG\approx\Delta MOP[/tex]
Now, from the given figure,
[tex]\begin{gathered} \frac{BG}{MP}=\frac{60}{90} \\ =\frac{2}{3} \end{gathered}[/tex]
Since,
[tex]\frac{IG}{OM}\ne\frac{2}{3}[/tex]
Therefore, these two sides are not similar.
We can say that MO and BI are similar. Therefore,
[tex]\begin{gathered} \frac{BI}{MO}=\frac{v}{27}=\frac{2}{3} \\ v=\frac{2\times27}{3} \\ =18 \end{gathered}[/tex]
Thus, the value of v is 18.
