Respuesta :

Given equation:

[tex]\frac{\frac{4x^2+12x-16}{2x+10}}{\frac{6x+24}{x^2+9x+20}}[/tex]

let us now simplify,

[tex]\begin{gathered} \frac{\frac{4x^2+12x-16}{2x+10}}{\frac{6x+24}{x^2+9x+20}} \\ =\frac{(4x^2+12x-16)(x^2+9x+20)}{(2x+10)(6x+24)} \\ =\frac{4(x^2+3x-4)(x^2+9x+20)}{12(x+5)(x+4)} \\ =\frac{\mleft(x^2+3x-4\mright)(x^2+9x+20)_{}}{3(x+5)(x+4)} \\ =\frac{(x+4)^2(x-1)(x+5)}{3(x+5)(x+4)} \\ =\frac{(x+4)(x-1)}{3} \end{gathered}[/tex]

the answer is option 2.

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