Respuesta :

We have:

[tex]cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}[/tex]

Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:

[tex]-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}[/tex]

We clear f(x):

[tex]f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}[/tex]

we simply what we can:

[tex]f(x)=\frac{1}{\frac{sin^2(x)+cos^2(x)}{sin(x)}}=sin(x)[/tex]

Thus, the correct answer is;

[tex]f(x)=sin(x)[/tex]

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