Simplify and write the trig expression in terms of sin and cos

We have:
[tex]cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}[/tex]Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:
[tex]-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}[/tex]We clear f(x):
[tex]f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}[/tex]we simply what we can:
[tex]f(x)=\frac{1}{\frac{sin^2(x)+cos^2(x)}{sin(x)}}=sin(x)[/tex]Thus, the correct answer is;
[tex]f(x)=sin(x)[/tex]