We are told that the ratios between areas of two circles are 9 to 16, this means the following:
[tex]\frac{A_1}{A_2}=\frac{9}{16}[/tex]Since the area of a circle is given by the following formula:
[tex]A=\pi r^2[/tex]Replacing in the proportion:
[tex]\frac{\pi r^2_{1^{}}}{\pi r^2_2}=\frac{9}{16}[/tex]canceling out the pis:
[tex]\frac{r^2_1}{r^2_2}=\frac{9}{16}[/tex]Now we use the following property of exponents:
[tex]\frac{a^2}{b^2}=(^{}\frac{a}{b})^2[/tex]Applying the property:
[tex](\frac{r_1}{r_2})^2=\frac{9}{16}[/tex]Now we take the square root to both sides:
[tex]\frac{r_1}{r_2}=\sqrt[]{\frac{9}{16}}[/tex]Solving:
[tex]\frac{r_1}{r_2}=\frac{3}{4}[/tex]Therefore, the radius is at a proportion of 3 to 4.