Solve for x:
[tex]log_x\left(\frac{1}{64}\right)=-2[/tex]Applying the definition of logarithms:
[tex]x^{-2}=\frac{1}{64}[/tex]Operating:
[tex]\frac{1}{x^2}=\frac{1}{64}[/tex]Applying square root:
[tex]\begin{gathered} \frac{1}{x}=\frac{1}{8} \\ \\ \text{ Or, equivalently:} \\ \\ x=8 \end{gathered}[/tex]
