Question

In the paper airplane shown, ABCD = EFGH , m < B = m < BCD = 90 , and m < BAD = 125 . Find m< GHE .

Answer 1

Ok, so:

Let me put the figure here below:

Ok, we have these facts:

The angle B measures 90°

The angle BCD measures 90°

The angle BAD measures 125°.

Now, it would be useful to find the measure of the angle ADC and then see what happen with GHE.

So, we know that the sum of the internal angles of a quadrilateral is equal to 360°, and the figure we got is actually a quadrilateral. So:

90° + 90° + 125° + ADC = 360°

ADC = 360° - 90° - 90° - 125°

ADC = 55°.

Now, notice that the next figure is a similar quadrilateral of the first one, and it has the same angles.

So, the mesure of angle GHE = the measure of angle ADC.

So, m