The probability of choosing an A is:
[tex]P(A)=\frac{2}{12}=\frac{1}{6}[/tex]The probability of choosing an I is:
[tex]P(I)=\frac{2}{12}=\frac{1}{6}[/tex]The probability of choosing an A or an I is the sum of both probabilities:
[tex]P(A\cup I)=\frac{1}{6}+\frac{1}{6}=\frac{2}{6}=\frac{1}{3}[/tex]It means that the answer is 1/3.