We need to solve for x and y.
Let's substitute the first equation in the second equation and solve for x. The process is shown below:
[tex]\begin{gathered} 7y-6=3x \\ 7(3x-30)-6=3x \\ 21x-210-6=3x \\ 21x-3x=210+6 \\ 18x=216 \\ x=\frac{216}{18} \\ x=12 \end{gathered}[/tex]Now, using the value of x, we can use the first equation to solve for y. The process is shown below:
[tex]\begin{gathered} y=3x-30 \\ y=3(12)-30 \\ y=36-30 \\ y=6 \end{gathered}[/tex]The correct answer:
