Given:
[tex]e^{3x}+4=50[/tex]Find: Value of "x" in logarithm.
Sol:
[tex]\begin{gathered} e^{3x}+4=50 \\ e^{3x}=50-4 \\ e^{3x}=46 \end{gathered}[/tex]Take log both sides.
[tex]\begin{gathered} \log_{_e}e^{3x}=\log_e46 \\ 3x=\log_e46 \\ x=\frac{\log_e46}{3} \end{gathered}[/tex]
