Question

Ahmad is choosing at random from a bag of colored marbles. The probability he will choose a green marble is 8/9. What are the odds in favor of him choosing a
green marble

Answer 1

Given:

The probability of selecting a green marble is P(G) = 8/9.

The objective is to find the odds in favor of choosing green marble.

Explanation:

In general, the probability of an event and its odd event is always 1.

So, the given event can be written as,

$P(G)+P(\bar{G})=1\text{ . . . . . (1)}$

On plugging the given values in equation (1),

$\frac{8}{9}+P(\bar{G})=1$

On further solving the above equation,

$\begin{gathered} P(\bar{G})=1-\frac{8}{9} \\ =\frac{9-8}{9} \\ =\frac{1}{9} \end{gathered}$

Hence, the odds in favor of choosing green marble is 1/9.