Question

Plot points between and beyond each X intercept and vertical asymptote find the value of the function at the given value of XI tried one of them I think I need further explanation please and thank you

Answer 1

Given:

$f(x)\text{ = }\frac{5x}{x^2-4}$

Then,

$f(-7)\text{ = }\frac{5(-7)}{(-7)^2-4}=-\frac{7}{9}$$f(-5)\text{ = }\frac{5(-5)}{(-5)^2-4}=-\frac{25}{21}$

$f(-1)\text{ = }\frac{5(-1)}{(-1)^2-4}=\frac{5}{3}\text{ }$$f(1)\text{ = }\frac{5(1)}{(1)^2-4}=-\frac{5}{3}$$f(6)\text{ = }\frac{5(6)}{(6)^2-4}=\frac{15}{16}$$f(8)\text{ = }\frac{5(8)}{(8)^2-4}=\frac{2}{3}$