Question

Find the mean, median, and mode of the list of values. Round to the nearest tenth if necessary.31, 10, 12, 6, 11, 32, 10, 10

Answer 1

Given:

$31,10,12,6,11,32,10,10$

a) Mean

$\begin{gathered} Mean=\frac{31+10+12+6+11+32+10+10}{8} \\ =\frac{122}{8} \\ =15.25 \\ \approx15.3 \end{gathered}$

b) Median

Arrange the terms in ascending order.

$6,\: 10,\: 10,\: 10,\: 11,\: 12,\: 31,\: 32$

As a number of terms are 8 that is even. So, median is the arithmetic mean of two middle terms.

$\frac{10+11}{2}=\frac{21}{2}=10.5$

c) mode

The term in the data set that appears most is 10.

Mode is 10

Answer: option b)

Mean = 15.3

median = 10.5

mode = 10