Given a cylinder of radius = r = 6 ft, and a height = h = 10 ft
A conic portion removed from the cylinder
So, the volume of the remaining portion =
the volume of the cylinder - the volume of the cone
The volume of the cylinder =
[tex]\pi\cdot r^2\cdot h[/tex]
The volume of the cone =
[tex]\frac{1}{3}\pi\cdot r^2\cdot h[/tex]
so, the answer will be =
[tex]\pi\cdot r^2\cdot h-\frac{1}{3}\pi\cdot r^2\cdot h=\frac{2}{3}\cdot\pi\cdot r^2\cdot h=\frac{2}{3}\pi\cdot6^2\cdot10=240\pi[/tex]
So, the answer is option 3) 240pi
