We have the following inequality given:
[tex]-4(x+7)<3(x-2)[/tex]For this case we can distribute the -4 and 3 and we got:
[tex]-4x\text{ }-28\text{ < 3x}-6[/tex]Now we can subtract 3x from both sides of the inequality and we got:
[tex]-4x-3x-28<3x-3x-6[/tex][tex]-7x-28<-6[/tex]Now we can add 28 in both sides of the inequality and we got:
[tex]-7x-28+28<-6+28[/tex][tex]-7x<22[/tex]