Question

A supermarket is holding a raffle for a new wrist watch. Out of the 500 tickets sold, David buys ticketsnumbered 5, 6, 7, and 8. What are the odds in favor of David's winning the raffle?O 1124O 124O 5001O 1:500

Answer 1

Given:

Number of tickets sold = 500

Number of tickets David bought (5, 6, 7, and 8) = 4 tickets

Let's find the odds in favor of David's winning the raffle.

To find the odds in favor, apply the formula:

$\begin{gathered} odds=P(\text{James will win) : P(James will not win)} \\ \\ \text{odds}=\frac{P(\text{James will win)}}{P(James\text{ will not win)}} \end{gathered}$

Thus, we have:

$\begin{gathered} odds=\frac{\frac{4}{500}}{\frac{500-4}{500}} \\ \\ odds=\frac{\frac{1}{125}}{\frac{496}{500}} \\ \\ \text{odds}=\frac{\frac{1}{125}}{\frac{125}{124}} \\ \\ \text{odds}=\frac{1}{125}\ast\frac{125}{124} \\ \\ \text{odds}=\frac{1}{124} \\ \\ \text{odds}=1\colon124 \end{gathered}$

Therefore, the odds in favor of David's wining the raffle is 1 : 124

ANSWER:

1 : 124