we have
20 objects
8 black
7 red
rest white
20-8-7= 5
5 white
since we are selecting 3 object at once
1) probability that one is black, one is red and the remaining one is white.
[tex]P(brw)=p(b)*p(r)*p(w)[/tex][tex]P(brw)=\frac{8}{20}*\frac{7}{20}*\frac{5}{20}[/tex][tex]P(brw)=\frac{280}{8000}=\frac{7}{200}\frac{}{}[/tex][tex]P(brw)=0.035[/tex]
1) probability one is black, one is red and the remaining one is white. is 0.035 or 3,5%
ii) exactly two are red.
[tex]p(rrx)=p(r)*p(r)*p(X)[/tex]
lets assume x is any ball
then p(x) is the probability of ge any ball = 1
[tex]p(rrx)=\frac{7}{20}*\frac{7}{20}*1[/tex][tex]p(rrx)=\frac{49}{400}[/tex][tex]p(rrx)=0.1225[/tex]
the probability of exactly two are red. is 0.1225 or 12,25%
iii)none of them is white.
[tex]1-p(w)=1-(\frac{5}{20})[/tex][tex]1-p(w)=\frac{3}{4}[/tex][tex]1-p(w)=\frac{3}{4}=0.75[/tex]
the probability that none is white is 0.75 or 75%