Question

the position from its starting point of a small plane preparing for takeoff is given by x(t)=1.64t^2 meters…

Answer 1

Given:

The position of the small plane is given by,

$x(t)=1.64t^2$

Explanation:

The accelration of plane can be obtained by double derivative of the position function.

Determine the double derivative of the position function.

$\begin{gathered} \frac{d^2}{dt^2}x(t)=\frac{d^2}{dt^2}(1.64t^2) \\ a(t)=1.64\cdot\frac{d}{dt}(2t) \\ =3.28\cdot1 \\ =3.28 \end{gathered}$

So acceleration of the small plane is 3.28 m/s^2

Answer: 3.28