Question

in point a the diameter is 12 C D equals 8 and MCD equals 90 find a measure round to the nearest hundred

Answer 1

Given that BE is diameter and CD is perpendicular, we can deduct that arcs CE and DE are equal.

$\begin{gathered} arc(CD)=arc(CE)+arc(DE) \\ 90=2\cdot arc(CE) \\ \text{arc(CE)}=45=arc(DE) \end{gathered}$

Therefore, arc DE is 45°.