Given
Point
(-5, 0)
Slope
-0.3
Procedure
a) Parallel
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
m = -0.3
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(-5,0). When x of the line is -5, y of the line must be 0.
[tex]\begin{gathered} b=y-mx \\ b=0-(-0.3)\cdot(-5) \\ b=-1.5 \end{gathered}[/tex]The equation of the line that passes through the point (-5,0) with a slope of -0.3
[tex]y=-0.3x-1.5[/tex]b) perpendicular
For perpendicular line m = 0.3
Now, what about b, the y-intercept?
[tex]\begin{gathered} b=y-mx \\ b=0-0.3\cdot(-5) \\ b=+1.5 \end{gathered}[/tex]The equation of the line that passes through the point (-5,0) with a slope of 0.3
[tex]y=0.3x+1.5[/tex]