Question

Solve for 4x^2+8x+3=0

Answer 1

Given the following equation:

$4x^2+8x+3=0$

We will factor the equation to solve for x:

$\begin{gathered} (2x+3)(2x+1)=0 \\ \end{gathered}$

So, there are two values for x that can be calculated as follows:

$\begin{gathered} 2x+3=0\to2x=-3\to x=\frac{-3}{2} \\ \\ 2x+1=0\to2x=-1\to x=\frac{-1}{2} \end{gathered}$

So, the answer will be:

$x=\lbrace\frac{-3}{2},\frac{-1}{2}\rbrace$