Given that the mass of the tank is m =10000 kg.
The initial speed is
[tex]v_o=7\text{ m/s}[/tex]The final speed is
[tex]v_f=0\text{ m/s}[/tex]As the tank comes to rest.
The time is t = 1.5 s
We have to find the average net force.
The formula to calculate force is
[tex]F=m\text{ }\times\frac{v_f-v_o}{t}[/tex]Substituting the values, the force will be
[tex]\begin{gathered} F=10000\times\frac{0-7}{1.5} \\ =-4.6666.67\text{ N} \end{gathered}[/tex]The negative sign indicates that the tank is slowing down or decelerating.
The magnitude of the force exerted by the tank on the barrier is 46666.67 N
