Answer:
The pressure of the sample is 1.18atm.
Explanation:
1st) The given information from the exercise is:
- Number of moles (n): 1.24moles
- Volume (V): 24.5L
- Temperature (T): 284K
- Ideal gas constant: 0.0821 atm*L/mol*K
2nd) With the Ideal Gases formula, we can replace the values of n, V and T to calculate the pressure of the sample:
[tex]\begin{gathered} P*V=n*R*T \\ P*24.5L=1.24mol*0.0821\frac{atm*L}{mol*K}*284K \\ P*24.5L=28.91atm*L \\ P=\frac{28.91atm*L}{24.5L} \\ P=1.18atm \end{gathered}[/tex]So, the pressure of the sample is 1.18atm.