Since ABCD and EFGH are similar
∴ Their corresponding sides are proportion (have equal ratios)
[tex]\therefore\frac{AB}{EF}=\frac{BC}{FG}=\frac{CD}{GH}=\frac{AD}{HE}[/tex]
∵ BC = 6 and FG = 3
∵ CD = 4
→ Substitute then in the 2nd and 3rd ratio above to find GH
[tex]\because\frac{6}{3}=\frac{4}{GH}[/tex]
→ By using cross multiplication
∴ 6 x GH = 3 x 4
∴ 6GH = 12
→ Divide both sides by 6 to find GH
[tex]\begin{gathered} \therefore\frac{6Gh}{6}=\frac{12}{6} \\ \therefore GH=2 \end{gathered}[/tex]
