Respuesta :

We will determine it as follows:

*We can see that the triangle has the following vertex:

A(1, 3)

B(3, 7)

C(5, 3)

Now, we determine the directional segments:

[tex]AB=(3-1,7-3)\Rightarrow AB=(2,4)[/tex][tex]AC=(5-1,3-3)\Rightarrow AC=(4,0)[/tex][tex]BC=(5-3,3-7)\Rightarrow BC=(2,-4)[/tex]

Now, we determine the distance of each segment:

[tex]d_{AB}=\sqrt[]{2^2+4^2}\Rightarrow d_{AB}=2\sqrt[]{5}[/tex][tex]d_{AC}=\sqrt[]{4^2+0^2}\Rightarrow d_{AC}=4[/tex][tex]d_{BC}=\sqrt[]{2^2+(-4)^2}\Rightarrow d_{BC}=2\sqrt[]{5}[/tex]

From this, we have that the triangle is isosceles.

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