STEP 1
We need to find the area of the two shapes.
[tex]\begin{gathered} \text{Area of rectangle = length x breadth = }8\text{ x 10 = 80 sq ft} \\ \text{Area of trapezoid = }\frac{1}{2}(upper\text{ length + lower length) x perpendicular height} \\ =\text{ }\frac{1}{2}(10+20)\text{ x }5\text{ =75 sq ft} \end{gathered}[/tex]STEP 2
We get the difference between the 2 areas.
80 - 75 = 5 sq ft
Therefore, area of rectangle is greater than that of trapezoid by 5 sq ft (Option 4)