Question

A sample of helium gas occupies 12.4 L at 23°C and 0.956 atm. What volume will itoccupy at 40°C and 1.20 atm?

Answer 1

Answer

V2 = 10.4 L

Explanation

Given:

Volume 1 = 12.4 L

Volume 2 = ?

Temperature 1 = 23°C = 296 K

Temperature 2 = 40°C = 313 K

Pressure 1 = 0.956 atm

Pressure 2 = 1.20 atm

Required: Volume 2

Solution:

The equation to solve this problem is the following:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

V2 = (P1 x V1 x T2)/(T1 x P2)

V2 = (0.956 x 12.4 x 313)/(296 x 1.20)

V2 = 10.4 L