Given:
[tex]\frac{y^{12}}{y^{12}}=???[/tex]so, as the numerator = denominator
the value of the given equation = 1
[tex]\frac{y^{12}}{y^{12}}=y^{12-12}=y^0=1[/tex]To find the value of y which satisfy the equation:
As the denominator must be not equal to zero
so, y is all real numbers except zero
So,
[tex]y=R-\mleft\{0\mright\}[/tex]