First, find the increasing functions. Then, classify each increasing function as having a larger or a smaller unit rate than the function represented in the graph.

To identify the increasing functions you need to identify the unit rate (rate of change) in each function, to be an increasing function the unit rate needs to be a possitive amount.
In a equation written in the form y=mx+b the unit rate is m
Then, for the given functions the increasing functions are:
[tex]\begin{gathered} y=\frac{4}{3}x-\frac{5}{3} \\ \\ y=\frac{5}{4}x-3 \\ \\ y=\frac{7}{4}x-\frac{9}{4} \\ \\ y=\frac{6}{5}x-\frac{3}{5} \\ \\ y=\frac{8}{5}x-\frac{7}{5} \end{gathered}[/tex]_____________
To idenify the unit rate of the graphed function use two points (x,y) in the next formula:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \\ \text{Points: (0,-2)(2,1)} \\ \\ m=\frac{1-(-2)}{2-0}=\frac{1+2}{2}=\frac{3}{2} \end{gathered}[/tex]Then, for the given increasing functions the next have a larger unit rate:
[tex]\begin{gathered} m=\frac{3}{2}=1.5 \\ \\ \\ y=\frac{7}{4}x-\frac{9}{4}(m=\frac{7}{4}=1.75) \\ \\ y=\frac{8}{5}x-\frac{7}{5}(m=\frac{8}{5}=1.6) \end{gathered}[/tex]And for the given increasing function the next have a smaller unit rate:
[tex]\begin{gathered} m=\frac{3}{2}=1.5 \\ \\ y=\frac{4}{3}x-\frac{5}{3}(m=\frac{4}{3}=1.33) \\ \\ y=\frac{5}{4}x-3(m=\frac{5}{4}=1.25) \\ \\ y=\frac{6}{5}x-\frac{3}{5}(m=\frac{6}{5}=1.2) \end{gathered}[/tex]