We know that Jack has narrowed down his selection to a total of:
[tex]7+7+4+4=22[/tex]
items.
Since he wants all the cheeses and he wants to use the express lane he needs to select a total of:
[tex]15-4=11[/tex]
more items.
From the total number of items he will select:
[tex]22-4=18[/tex]
items.
Then he needs to select 11 item from 18 possible items. To determine in how many ways can do this we can use a combination, a combination is given by:
[tex]C(n,r)=\frac{n!}{r!(n-r)!}[/tex]
Then we have:
[tex]C(18,11)=\frac{18!}{11!(18-11)!}=31824[/tex]
Therefore, there are 31824 ways Jack can choose 15 items if he wants all the cheeses