Question

I am just going to have to send you a photo of the question because the photo is to large to send this way.

Answer 1

$\begin{gathered} \frac{3+n-2n^2}{1+n} \\ \frac{-2n^2+n+3}{n+1} \\ \frac{-2\cdot(n^2-\frac{1}{2}n-\frac{3}{2})}{n+1} \\ \frac{-2\cdot((n-\frac{3}{2})\cdot(n+1))}{n+1} \\ -2\cdot(n-\frac{3}{2}) \\ -2n+3=3-2n \end{gathered}$