Question

I have missing work may someone help me with my math

Answer 1

2)

$w^2-3,\quad w=4$

When we say that w = 4, it means that we can rewrite the expression and instead of "w", we will put "4", so

$w^2-3\Rightarrow4^2-3$

Now we have a numerical expression to solve, we can easily solve it!

$\begin{gathered} 4^2-3 \\ \\ 4\cdot4-3 \\ \\ 16-3 \\ \\ 13 \end{gathered}$

Therefore, the final answer is

$4^2-3=13$

5)

Here we will do the same thing, the "hard" part is solving the numeric expression, it will be a little bit harder than the 2).

$3(6m-17),\quad m=5$

Again, repeat the same process, rewrite the expression, and instead of "m" you put "5"

$3(6m-17)\Rightarrow3(6\cdot5-17)$

Again, another expression to simplify, remember that we always solve what is inside ( ) first, and we have a multiplication inside ( ) so we must solve it first

$3(6\cdot5-17)=3(30-17)$

Now we solve the multiplication inside ( ) we can do the subctration

$3(30-17)=3\cdot(13)$

The last step is just to solve another multiplication

$3\cdot(13)=39$

Now we simplified everything we can have the final answer:

$3(6\cdot5-17)=39$

6)

Here we have a division, but it's similar with 5) and 2), we have

$\frac{2a}{3}+13,\quad a=15$

No secrets, repeat the process, but here, "a" will turn into "15", then

$\frac{2a}{3}+13\Rightarrow\frac{2\cdot15}{3}+13$

We can do the multiplication at the numerator of the fraction

$\frac{2\cdot15}{3}+13=\frac{30}{3}+13$

Now we can simplify the fraction, 30 divided by 3 is 10, then

$\frac{30}{3}+13=10+13$

Now just do the sum and it's done!

$10+13=23$

Hence the final answer is

$\frac{2\cdot15}{3}+13=23$

ANSWERS:

1) 43

2) 13

3) 67

4) 12

5) 39

6) 23