Question

Given g(x) = 1/x^3Explain if the question cannot be solved

Answer 1

Given

$g(x)=\frac{1}{x^3}$

To find:

$\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}g(x)dx$

Explanation:

It is given that,

$g(x)=\frac{1}{x^3}$

That implies,

$\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}g(x)dx$