Solve the system of equations;
[tex]\begin{gathered} x+3y=15---(1) \\ 2x+2y=14---(2) \\ In\text{ equation (1), make x the subject of the equation} \\ \text{Therefore, you'll now have} \\ x=15-3y \\ \text{Substitute for the value of x into equation (2)} \\ 2(15-3y)+2y=14 \\ 30-6y+2y=14 \\ \text{Collect all like terms and you'll have,} \\ 30-14=6y-2y \\ 16=4y \\ \text{Divide both sides by 4 and you'll have} \\ 4=y \\ \text{Next you substitute for the value of y into equation (1)} \\ x+3y=15 \\ x+3(4)=15 \\ x+12=15 \\ \text{Subtract 12 from both sides and you'll have,} \\ x=3 \end{gathered}[/tex]Therefore, the correct answer is
x = 3, y = 4
