Respuesta :

[tex]\frac{2x\text{ + 1}}{3x\text{ + 2}}[/tex]

Aquí, queremos evaluar las expresiones entre paréntesis;

(1/(1+(1/(1+(1/(1+(1/x)))))))

= (1/(1+(1/(1+(1/(1+1/x))))))

= (1/(1+(1/(1+(1/(x+1)/x))))

= (1/(1+(1/(1+(x/(x+1))))

= (1/(1+(1/((x+1+x)/(x+1))))

= (1/(1+(1/((2x+1/(x+1)))

= (1/(1+(x+1/(2x+1)

= (1/(2x + 1+(x+1/(2x+1)

= (1/(3x+2)/(2x+1)

= (2x+1)/(3x+2)

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