Question

for the given function, state the amplitude and the minimum output for the function: f(t)=3cos(6/5t)

Answer 1

we have the function

f(t)=3cos(6/5t)

The amplitude of the given function is A=3

The minimum value of the function cosine is for t=-pi

so

(6/5)t=-pi

solve for t

t=-5pi/6

y=3cos((6/5)((5pi/6))

y=3cos(-pi)

y=3(-1)

y=-3

the minimum value is y=-3

therefore

The amplitude is 3 and te minimum is -3